Resolviendo la fuerza de reacción de los rodamientos en problemas mecánicos
FR=4*4=16KN
FX=0
FY=0,-FNA FBY-FR FNC=FBY FNC-22=0
MB( F)=0, MB(F)= FNA * 2-ME-FR * 2 FNC * 4 = FNC * 4-30 = 0
FNC = 7,5 kilonewtons FBY = 14,5 kilonewton
FX=0
FY=0,-FNA FBY-FR FNC=FBY FNC-22=0
MB( F)=0, MB(F)= FNA * 2-ME-FR * 2 FNC * 4 = FNC * 4-30 = 0
FNC = 7,5 kilonewtons FBY = 14,5 kilonewton